i have link button inside gridview. can some one help me to form proper URL for this
<asp:TemplateField HeaderText="View" >
<ItemTemplate><asp:LinkButton runat="server" ID="lnkView" OnClientClick="OpenDialog('/SitePages/View%20Booking.aspx?','','');return false;" ><%#Eval("Booking Name") %></asp:LinkButton>
</ItemTemplate>
</asp:TemplateField>
if i use above, than popup opens fine on link button click but if append parameter as shown below, it throws error on load itself.
<asp:LinkButton runat="server" ID="lnkView" OnClientClick="OpenDialog('/SitePages/View%20Booking.aspx?BID="+ Eval("ID")+"','','');return false;" ><%#Eval("Booking Name") %></asp:LinkButton>
can some one help to form proper URL?
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